Se x = 1+5.4−121 + 3−1 e y =31−7.2−3(21 +3 −1)−1 , então

Q1861196

Se $x = \frac{2 ^{1} + 3 ^{- 1}}{1 + 5 . 4 ^{- 1}}$ e $y = \frac{( 2 ^{1} + 3 ^{- 1} ) ^{^{- 1}}}{3 1 - 7 . 2 ^{- 3}}$ , então

$x < y < 0$

$x + y = \frac{2 1}{5}$

$x . y = \frac{4}{3}$

$x^{- 1} . y^{- 1} = \frac{2 9}{2 0}$

Se x = 1+5.4−1​21 + 3−1​ e y =31−7.2−3​(21 +3 −1)−1​ , então